Differentiate the following w.r.t x Exercise 1.1
3)Differentiate the following w.r.t x :
(xi)$\frac{e^{\sqrt{x}}+1}{e^{\sqrt{x}}-1}$
Solution:
$\frac{dy}{dx}=\frac{d}{dx}\left(\frac{e^{\sqrt{x}}+1}{e^{\sqrt{x}}-1}\right)$
$=\frac{(e^{\sqrt{x}}-1)\frac{d}{dx}(e^{\sqrt{x}}+1)-(e^{\sqrt{x}}+1)\frac{d}{dx}(e^{\sqrt{x}}-1)}{(e^{\sqrt{x}}-1)^2}$
$=\frac{(e^{\sqrt{x}}-1)(e^{\sqrt{x}}\frac{d}{dx}\sqrt{x}+0)-(e^{\sqrt{x}}+1)(e^{\sqrt{x}}\frac{d}{dx}\sqrt{x}-0)}{(e^{\sqrt{x}}-1)^2}$
$=\frac{(e^{\sqrt{x}}-1)(e^{\sqrt{x}}\frac{1}{2\sqrt{x}})-(e^{\sqrt{x}}+1)(e^{\sqrt{x}}\frac{1}{2\sqrt{x}})}{(e^{\sqrt{x}}-1)^2}$
(iv)$\frac{(x^3-5)^5}{(x^3+5)^3}$
(xii)$log\left[ tan^3xsin^4x(x^2+7)\right]$
(xiii)$log\left[\sqrt{\frac{1-cos3x}{1+cos3x}}\right]$
(xiv)$log\left[\sqrt{\frac{1+cos\frac{5x}{2}}{1-cos\frac{5x}{2}}}\right]$
(xv)$log\left[\sqrt{\frac{1-sinx}{1+sinx}}\right]$
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| Differentiate following w.r.t x Exercise 1.1 XIl |




